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Holy See unveils new details about Apostolic visit to Poland starting tomorrow

.- Tomorrow, Thursday, Benedict XVI will leave the Vatican on an apostolic trip to Poland, the second of his pontificate following last August's visit to Germany. In Poland, from May 25 to 28, he will visit Warsaw, Czestochowa, Krakow, Wadowice, Kalwaria Zebrzydowska, and Auschwitz.

He will depart from Rome's Fiumicino airport at 8.40 a.m., arriving in Warsaw at 11 a.m. Following the welcome ceremony at Warsaw's Okecie airport, he will travel by popemobile to the city's cathedral of St. John. He will hold a meeting with the clergy there.

At 5.45 p.m. he is due to pay a courtesy visit to the president of Poland, Lech Kaczynski, in the presidential palace.

Leaving the presidential palace at 6.45 p.m., he will travel to the Lutheran church of the Most Holy Trinity where he is due to meet with delegates of the seven Churches form the Polish Ecumenical Council. The Lutheran church of the Most Holy Trinity was built in 1781 in a poor area on the outskirts of Warsaw.

Following the ecumenical meeting, the Pope will return to the apostolic nunciature, where he will spend the night.

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